(x-3)(2x^2+2x-4)=0

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Solution for (x-3)(2x^2+2x-4)=0 equation:


Simplifying
(x + -3)(2x2 + 2x + -4) = 0

Reorder the terms:
(-3 + x)(2x2 + 2x + -4) = 0

Reorder the terms:
(-3 + x)(-4 + 2x + 2x2) = 0

Multiply (-3 + x) * (-4 + 2x + 2x2)
(-3(-4 + 2x + 2x2) + x(-4 + 2x + 2x2)) = 0
((-4 * -3 + 2x * -3 + 2x2 * -3) + x(-4 + 2x + 2x2)) = 0
((12 + -6x + -6x2) + x(-4 + 2x + 2x2)) = 0
(12 + -6x + -6x2 + (-4 * x + 2x * x + 2x2 * x)) = 0
(12 + -6x + -6x2 + (-4x + 2x2 + 2x3)) = 0

Reorder the terms:
(12 + -6x + -4x + -6x2 + 2x2 + 2x3) = 0

Combine like terms: -6x + -4x = -10x
(12 + -10x + -6x2 + 2x2 + 2x3) = 0

Combine like terms: -6x2 + 2x2 = -4x2
(12 + -10x + -4x2 + 2x3) = 0

Solving
12 + -10x + -4x2 + 2x3 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(6 + -5x + -2x2 + x3) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(6 + -5x + -2x2 + x3)' equal to zero and attempt to solve: Simplifying 6 + -5x + -2x2 + x3 = 0 Solving 6 + -5x + -2x2 + x3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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